Base | Representation |
---|---|
bin | 1100001100100111111011… |
… | …0011011101000001001100 |
3 | 1202111002011201022220110122 |
4 | 3003021332303131001030 |
5 | 3224211224410044112 |
6 | 44304534013124112 |
7 | 2552625314214062 |
oct | 303117663350114 |
9 | 52432151286418 |
10 | 13411015315532 |
11 | 430064158074a |
12 | 1607189a89638 |
13 | 763865454233 |
14 | 34514d124032 |
15 | 183cb8147872 |
hex | c327ecdd04c |
13411015315532 has 6 divisors (see below), whose sum is σ = 23469276802188. Its totient is φ = 6705507657764.
The previous prime is 13411015315487. The next prime is 13411015315561. The reversal of 13411015315532 is 23551351011431.
13411015315532 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13411015315492 and 13411015315501.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1676376914438 + ... + 1676376914445.
It is an arithmetic number, because the mean of its divisors is an integer number (3911546133698).
Almost surely, 213411015315532 is an apocalyptic number.
It is an amenable number.
13411015315532 is a deficient number, since it is larger than the sum of its proper divisors (10058261486656).
13411015315532 is a wasteful number, since it uses less digits than its factorization.
13411015315532 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3352753828887 (or 3352753828885 counting only the distinct ones).
The product of its (nonzero) digits is 27000, while the sum is 35.
Adding to 13411015315532 its reverse (23551351011431), we get a palindrome (36962366326963).
The spelling of 13411015315532 in words is "thirteen trillion, four hundred eleven billion, fifteen million, three hundred fifteen thousand, five hundred thirty-two".
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