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13411015315532 = 223352753828883
BaseRepresentation
bin1100001100100111111011…
…0011011101000001001100
31202111002011201022220110122
43003021332303131001030
53224211224410044112
644304534013124112
72552625314214062
oct303117663350114
952432151286418
1013411015315532
11430064158074a
121607189a89638
13763865454233
1434514d124032
15183cb8147872
hexc327ecdd04c

13411015315532 has 6 divisors (see below), whose sum is σ = 23469276802188. Its totient is φ = 6705507657764.

The previous prime is 13411015315487. The next prime is 13411015315561. The reversal of 13411015315532 is 23551351011431.

13411015315532 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 13411015315492 and 13411015315501.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1676376914438 + ... + 1676376914445.

It is an arithmetic number, because the mean of its divisors is an integer number (3911546133698).

Almost surely, 213411015315532 is an apocalyptic number.

It is an amenable number.

13411015315532 is a deficient number, since it is larger than the sum of its proper divisors (10058261486656).

13411015315532 is a wasteful number, since it uses less digits than its factorization.

13411015315532 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3352753828887 (or 3352753828885 counting only the distinct ones).

The product of its (nonzero) digits is 27000, while the sum is 35.

Adding to 13411015315532 its reverse (23551351011431), we get a palindrome (36962366326963).

The spelling of 13411015315532 in words is "thirteen trillion, four hundred eleven billion, fifteen million, three hundred fifteen thousand, five hundred thirty-two".

Divisors: 1 2 4 3352753828883 6705507657766 13411015315532