Base | Representation |
---|---|
bin | 1100001100100111111101… |
… | …0001001100110010111011 |
3 | 1202111002012021000002010200 |
4 | 3003021333101030302323 |
5 | 3224211233404112103 |
6 | 44304534452213243 |
7 | 2552625440412306 |
oct | 303117721146273 |
9 | 52432167002120 |
10 | 13411023113403 |
11 | 4300645a17373 |
12 | 160719060a223 |
13 | 763866c54666 |
14 | 345150193b3d |
15 | 183cb8b880a3 |
hex | c327f44ccbb |
13411023113403 has 24 divisors (see below), whose sum is σ = 19737507928320. Its totient is φ = 8771754176640.
The previous prime is 13411023113347. The next prime is 13411023113407. The reversal of 13411023113403 is 30431132011431.
13411023113403 is a `hidden beast` number, since 1 + 3 + 4 + 1 + 1 + 0 + 2 + 311 + 340 + 3 = 666.
It is not a de Polignac number, because 13411023113403 - 213 = 13411023105211 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13411023113407) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 18359718 + ... + 19076196.
It is an arithmetic number, because the mean of its divisors is an integer number (822396163680).
Almost surely, 213411023113403 is an apocalyptic number.
13411023113403 is a deficient number, since it is larger than the sum of its proper divisors (6326484814917).
13411023113403 is a wasteful number, since it uses less digits than its factorization.
13411023113403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 755779 (or 755776 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
Adding to 13411023113403 its reverse (30431132011431), we get a palindrome (43842155124834).
The spelling of 13411023113403 in words is "thirteen trillion, four hundred eleven billion, twenty-three million, one hundred thirteen thousand, four hundred three".
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