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13411044521521 is a prime number
BaseRepresentation
bin1100001100101000000010…
…0010110111011000110001
31202111002020202021201112221
43003022000202313120301
53224211304344142041
644304540535121041
72552626120364533
oct303120042673061
952432222251487
1013411044521521
114300657009629
121607197813181
1376386b50b99a
14345152d67853
15183cba9b62d1
hexc32808b7631

13411044521521 has 2 divisors, whose sum is σ = 13411044521522. Its totient is φ = 13411044521520.

The previous prime is 13411044521389. The next prime is 13411044521561. The reversal of 13411044521521 is 12512544011431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13401925226496 + 9119295025 = 3660864^2 + 95495^2 .

It is a cyclic number.

It is not a de Polignac number, because 13411044521521 - 223 = 13411036132913 is a prime.

It is a super-2 number, since 2×134110445215212 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13411044521561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705522260760 + 6705522260761.

It is an arithmetic number, because the mean of its divisors is an integer number (6705522260761).

Almost surely, 213411044521521 is an apocalyptic number.

It is an amenable number.

13411044521521 is a deficient number, since it is larger than the sum of its proper divisors (1).

13411044521521 is an equidigital number, since it uses as much as digits as its factorization.

13411044521521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19200, while the sum is 34.

Adding to 13411044521521 its reverse (12512544011431), we get a palindrome (25923588532952).

The spelling of 13411044521521 in words is "thirteen trillion, four hundred eleven billion, forty-four million, five hundred twenty-one thousand, five hundred twenty-one".