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134112312403 = 418133207431
BaseRepresentation
bin111110011100110110…
…1110111110001010011
3110211011111222100201121
41330321231313301103
54144130222444103
6141335500143111
712455266563226
oct1747155676123
9424144870647
10134112312403
11519709a4323
1221ba9b37a97
13c853b5ac94
1466c36d75bd
15374ddc16bd
hex1f39b77c53

134112312403 has 4 divisors (see below), whose sum is σ = 134115561648. Its totient is φ = 134109063160.

The previous prime is 134112312349. The next prime is 134112312407. The reversal of 134112312403 is 304213211431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134112312403 - 229 = 133575441491 is a prime.

It is a super-2 number, since 2×1341123124032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134112312407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1561903 + ... + 1645528.

It is an arithmetic number, because the mean of its divisors is an integer number (33528890412).

Almost surely, 2134112312403 is an apocalyptic number.

134112312403 is a deficient number, since it is larger than the sum of its proper divisors (3249245).

134112312403 is an equidigital number, since it uses as much as digits as its factorization.

134112312403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3249244.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 134112312403 its reverse (304213211431), we get a palindrome (438325523834).

The spelling of 134112312403 in words is "one hundred thirty-four billion, one hundred twelve million, three hundred twelve thousand, four hundred three".

Divisors: 1 41813 3207431 134112312403