Base | Representation |
---|---|
bin | 10011100001000001101… |
… | …100101100010100000010 |
3 | 11202012200210112010122101 |
4 | 103201001230230110002 |
5 | 133433114244444414 |
6 | 2504035121501014 |
7 | 165615334113652 |
oct | 23410154542402 |
9 | 4665623463571 |
10 | 1341132031234 |
11 | 477853083036 |
12 | 197b064a176a |
13 | 99611864068 |
14 | 48ca8232362 |
15 | 24d44ebda74 |
hex | 13841b2c502 |
1341132031234 has 4 divisors (see below), whose sum is σ = 2011698046854. Its totient is φ = 670566015616.
The previous prime is 1341132031223. The next prime is 1341132031241. The reversal of 1341132031234 is 4321302311431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1269306423225 + 71825608009 = 1126635^2 + 268003^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335283007807 + ... + 335283007810.
Almost surely, 21341132031234 is an apocalyptic number.
1341132031234 is a deficient number, since it is larger than the sum of its proper divisors (670566015620).
1341132031234 is an equidigital number, since it uses as much as digits as its factorization.
1341132031234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 670566015619.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 1341132031234 its reverse (4321302311431), we get a palindrome (5662434342665).
The spelling of 1341132031234 in words is "one trillion, three hundred forty-one billion, one hundred thirty-two million, thirty-one thousand, two hundred thirty-four".
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