134114033113 has 4 divisors (see below), whose sum is σ = 134121016080. Its totient is φ = 134107050148.

The previous prime is 134114033111. The next prime is 134114033117. The reversal of 134114033113 is 311330411431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 134114033113 - 2¹ = 134114033111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134114033111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3462595 + ... + 3501112.

It is an arithmetic number, because the mean of its divisors is an integer number (33530254020).

Almost surely, 2^134114033113 is an apocalyptic number.

It is an amenable number.

134114033113 is a deficient number, since it is larger than the sum of its proper divisors (6982967).

134114033113 is an equidigital number, since it uses as much as digits as its factorization.

134114033113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6982966.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 134114033113 its reverse (311330411431), we get a palindrome (445444444544).

The spelling of 134114033113 in words is "one hundred thirty-four billion, one hundred fourteen million, thirty-three thousand, one hundred thirteen".