13411415053193 has 2 divisors, whose sum is σ = 13411415053194. Its totient is φ = 13411415053192.

The previous prime is 13411415053177. The next prime is 13411415053217. The reversal of 13411415053193 is 39135051411431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9812756731024 + 3598658322169 = 3132532^2 + 1897013^2 .

It is a cyclic number.

It is not a de Polignac number, because 13411415053193 - 2⁴ = 13411415053177 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13411415053193.

It is not a weakly prime, because it can be changed into another prime (13411415053133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705707526596 + 6705707526597.

It is an arithmetic number, because the mean of its divisors is an integer number (6705707526597).

Almost surely, 2^{13411415053193} is an apocalyptic number.

It is an amenable number.

13411415053193 is a deficient number, since it is larger than the sum of its proper divisors (1).

13411415053193 is an equidigital number, since it uses as much as digits as its factorization.

13411415053193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97200, while the sum is 41.

The spelling of 13411415053193 in words is "thirteen trillion, four hundred eleven billion, four hundred fifteen million, fifty-three thousand, one hundred ninety-three".