Base | Representation |
---|---|
bin | 1100001100101001011110… |
… | …0110000011011011011010 |
3 | 1202111010020200221201022021 |
4 | 3003022113212003123122 |
5 | 3224213102343430432 |
6 | 44305043151445054 |
7 | 2552641524363130 |
oct | 303122746033332 |
9 | 52433220851267 |
10 | 13411431233242 |
11 | 4300835328899 |
12 | 160728522678a |
13 | 763900679aa3 |
14 | 34518c46d750 |
15 | 183cde902697 |
hex | c32979836da |
13411431233242 has 32 divisors (see below), whose sum is σ = 23032772294400. Its totient is φ = 5737322223360.
The previous prime is 13411431233237. The next prime is 13411431233243. The reversal of 13411431233242 is 24233213411431.
It is a happy number.
13411431233242 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13411431233198 and 13411431233207.
It is not an unprimeable number, because it can be changed into a prime (13411431233243) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 59066692 + ... + 59293312.
It is an arithmetic number, because the mean of its divisors is an integer number (719774134200).
Almost surely, 213411431233242 is an apocalyptic number.
13411431233242 is a deficient number, since it is larger than the sum of its proper divisors (9621341061158).
13411431233242 is a wasteful number, since it uses less digits than its factorization.
13411431233242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 234286.
The product of its digits is 41472, while the sum is 34.
Adding to 13411431233242 its reverse (24233213411431), we get a palindrome (37644644644673).
The spelling of 13411431233242 in words is "thirteen trillion, four hundred eleven billion, four hundred thirty-one million, two hundred thirty-three thousand, two hundred forty-two".
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