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13411440770857 is a prime number
BaseRepresentation
bin1100001100101001100000…
…1010011011111100101001
31202111010021100220021110021
43003022120022123330221
53224213112314131412
644305044132120441
72552642001425443
oct303123012337451
952433240807407
1013411440770857
11430083a752618
121607288466121
1376390263904c
1434518d833493
15183ce0688607
hexc329829bf29

13411440770857 has 2 divisors, whose sum is σ = 13411440770858. Its totient is φ = 13411440770856.

The previous prime is 13411440770731. The next prime is 13411440770873. The reversal of 13411440770857 is 75807704411431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13022708472601 + 388732298256 = 3608699^2 + 623484^2 .

It is a cyclic number.

It is not a de Polignac number, because 13411440770857 - 227 = 13411306553129 is a prime.

It is a super-3 number, since 3×134114407708573 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13411440777857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705720385428 + 6705720385429.

It is an arithmetic number, because the mean of its divisors is an integer number (6705720385429).

Almost surely, 213411440770857 is an apocalyptic number.

It is an amenable number.

13411440770857 is a deficient number, since it is larger than the sum of its proper divisors (1).

13411440770857 is an equidigital number, since it uses as much as digits as its factorization.

13411440770857 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2634240, while the sum is 52.

The spelling of 13411440770857 in words is "thirteen trillion, four hundred eleven billion, four hundred forty million, seven hundred seventy thousand, eight hundred fifty-seven".