Base | Representation |
---|---|
bin | 1100001100101001100011… |
… | …0110111010111010000010 |
3 | 1202111010022011211201112112 |
4 | 3003022120312322322002 |
5 | 3224213123310311002 |
6 | 44305045230055322 |
7 | 2552642202514112 |
oct | 303123066727202 |
9 | 52433264751475 |
10 | 13411452432002 |
11 | 4300846297829 |
12 | 160729034a542 |
13 | 763904b8ca31 |
14 | 3451911cb042 |
15 | 183ce16dd852 |
hex | c3298dbae82 |
13411452432002 has 4 divisors (see below), whose sum is σ = 20117178648006. Its totient is φ = 6705726216000.
The previous prime is 13411452431999. The next prime is 13411452432029. The reversal of 13411452432002 is 20023425411431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8539901580721 + 4871550851281 = 2922311^2 + 2207159^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13411452432002.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3352863107999 + ... + 3352863108002.
Almost surely, 213411452432002 is an apocalyptic number.
13411452432002 is a deficient number, since it is larger than the sum of its proper divisors (6705726216004).
13411452432002 is an equidigital number, since it uses as much as digits as its factorization.
13411452432002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6705726216003.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 13411452432002 its reverse (20023425411431), we get a palindrome (33434877843433).
The spelling of 13411452432002 in words is "thirteen trillion, four hundred eleven billion, four hundred fifty-two million, four hundred thirty-two thousand, two".
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