Base | Representation |
---|---|
bin | 1100001100101001100011… |
… | …1101111000000110000011 |
3 | 1202111010022022021100220011 |
4 | 3003022120331320012003 |
5 | 3224213124242133431 |
6 | 44305045333125351 |
7 | 2552642224150315 |
oct | 303123075700603 |
9 | 52433268240804 |
10 | 13411454255491 |
11 | 4300847322846 |
12 | 1607290a89857 |
13 | 76390537aa16 |
14 | 3451915437b5 |
15 | 183ce194dcb1 |
hex | c3298f78183 |
13411454255491 has 2 divisors, whose sum is σ = 13411454255492. Its totient is φ = 13411454255490.
The previous prime is 13411454255477. The next prime is 13411454255579. The reversal of 13411454255491 is 19455245411431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13411454255491 - 215 = 13411454222723 is a prime.
It is not a weakly prime, because it can be changed into another prime (13411154255491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705727127745 + 6705727127746.
It is an arithmetic number, because the mean of its divisors is an integer number (6705727127746).
Almost surely, 213411454255491 is an apocalyptic number.
13411454255491 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411454255491 is an equidigital number, since it uses as much as digits as its factorization.
13411454255491 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1728000, while the sum is 49.
The spelling of 13411454255491 in words is "thirteen trillion, four hundred eleven billion, four hundred fifty-four million, two hundred fifty-five thousand, four hundred ninety-one".
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