Base | Representation |
---|---|
bin | 1100001100101001101111… |
… | …1111100110111111001001 |
3 | 1202111010102211211120000000 |
4 | 3003022123333212333021 |
5 | 3224213230242310403 |
6 | 44305054345433213 |
7 | 2552643411630126 |
oct | 303123377467711 |
9 | 52433384746000 |
10 | 13411505041353 |
11 | 4300872a5aa31 |
12 | 16072a5a9b809 |
13 | 763912a4ca23 |
14 | 3451981a374d |
15 | 183ce61317a3 |
hex | c329bfe6fc9 |
13411505041353 has 32 divisors (see below), whose sum is σ = 21172833091200. Its totient is φ = 8470424210400.
The previous prime is 13411505041351. The next prime is 13411505041367. The reversal of 13411505041353 is 35314050511431.
13411505041353 is a `hidden beast` number, since 1 + 3 + 4 + 1 + 15 + 0 + 504 + 135 + 3 = 666.
It is not a de Polignac number, because 13411505041353 - 21 = 13411505041351 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13411505041351) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 161336748 + ... + 161419853.
It is an arithmetic number, because the mean of its divisors is an integer number (661651034100).
Almost surely, 213411505041353 is an apocalyptic number.
It is an amenable number.
13411505041353 is a deficient number, since it is larger than the sum of its proper divisors (7761328049847).
13411505041353 is an frugal number, since it uses more digits than its factorization.
13411505041353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 322756641 (or 322756623 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 36.
Adding to 13411505041353 its reverse (35314050511431), we get a palindrome (48725555552784).
The spelling of 13411505041353 in words is "thirteen trillion, four hundred eleven billion, five hundred five million, forty-one thousand, three hundred fifty-three".
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