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134115215177 is a prime number
BaseRepresentation
bin111110011100111100…
…0111100011101001001
3110211011201102211120202
41330321320330131021
54144131443341202
6141340042301545
712455333343146
oct1747170743511
9424151384522
10134115215177
11519725a7209
1221baaab78b5
13c8546362b8
1466c3c513cd
15374e296802
hex1f39e3c749

134115215177 has 2 divisors, whose sum is σ = 134115215178. Its totient is φ = 134115215176.

The previous prime is 134115215167. The next prime is 134115215233. The reversal of 134115215177 is 771512511431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112996150201 + 21119064976 = 336149^2 + 145324^2 .

It is a cyclic number.

It is not a de Polignac number, because 134115215177 - 24 = 134115215161 is a prime.

It is a super-2 number, since 2×1341152151772 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 134115215177.

It is not a weakly prime, because it can be changed into another prime (134115215167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67057607588 + 67057607589.

It is an arithmetic number, because the mean of its divisors is an integer number (67057607589).

Almost surely, 2134115215177 is an apocalyptic number.

It is an amenable number.

134115215177 is a deficient number, since it is larger than the sum of its proper divisors (1).

134115215177 is an equidigital number, since it uses as much as digits as its factorization.

134115215177 is an evil number, because the sum of its binary digits is even.

The product of its digits is 29400, while the sum is 38.

The spelling of 134115215177 in words is "one hundred thirty-four billion, one hundred fifteen million, two hundred fifteen thousand, one hundred seventy-seven".