Base | Representation |
---|---|
bin | 1100001100101001110101… |
… | …1110110101101000101011 |
3 | 1202111010111120210211201211 |
4 | 3003022131132311220223 |
5 | 3224213303140130120 |
6 | 44305101040453551 |
7 | 2552644134051421 |
oct | 303123536655053 |
9 | 52433446724654 |
10 | 13411530005035 |
11 | 4300886060578 |
12 | 16072b231a2b7 |
13 | 763917c80536 |
14 | 34519b621111 |
15 | 183ce841325a |
hex | c329d7b5a2b |
13411530005035 has 16 divisors (see below), whose sum is σ = 16946280727200. Its totient is φ = 10161287571456.
The previous prime is 13411530005023. The next prime is 13411530005051. The reversal of 13411530005035 is 53050003511431.
It is not a de Polignac number, because 13411530005035 - 219 = 13411529480747 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13411530004988 and 13411530005006.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22203420 + ... + 22799449.
It is an arithmetic number, because the mean of its divisors is an integer number (1059142545450).
Almost surely, 213411530005035 is an apocalyptic number.
13411530005035 is a deficient number, since it is larger than the sum of its proper divisors (3534750722165).
13411530005035 is a wasteful number, since it uses less digits than its factorization.
13411530005035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45006030.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 13411530005035 its reverse (53050003511431), we get a palindrome (66461533516466).
The spelling of 13411530005035 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty million, five thousand, thirty-five".
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