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13411530005035 = 519313745002869
BaseRepresentation
bin1100001100101001110101…
…1110110101101000101011
31202111010111120210211201211
43003022131132311220223
53224213303140130120
644305101040453551
72552644134051421
oct303123536655053
952433446724654
1013411530005035
114300886060578
1216072b231a2b7
13763917c80536
1434519b621111
15183ce841325a
hexc329d7b5a2b

13411530005035 has 16 divisors (see below), whose sum is σ = 16946280727200. Its totient is φ = 10161287571456.

The previous prime is 13411530005023. The next prime is 13411530005051. The reversal of 13411530005035 is 53050003511431.

It is not a de Polignac number, because 13411530005035 - 219 = 13411529480747 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13411530004988 and 13411530005006.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22203420 + ... + 22799449.

It is an arithmetic number, because the mean of its divisors is an integer number (1059142545450).

Almost surely, 213411530005035 is an apocalyptic number.

13411530005035 is a deficient number, since it is larger than the sum of its proper divisors (3534750722165).

13411530005035 is a wasteful number, since it uses less digits than its factorization.

13411530005035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45006030.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 13411530005035 its reverse (53050003511431), we get a palindrome (66461533516466).

The spelling of 13411530005035 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty million, five thousand, thirty-five".

Divisors: 1 5 19 95 3137 15685 59603 298015 45002869 225014345 855054511 4275272555 141174000053 705870000265 2682306001007 13411530005035