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13411532340497 is a prime number
BaseRepresentation
bin1100001100101001110110…
…0111101111110100010001
31202111010111202012111101102
43003022131213233310101
53224213304234343442
644305101202514145
72552644162646354
oct303123547576421
952433452174342
1013411532340497
114300887406205
1216072b3065955
137639185ba575
1434519ba6c29b
15183ce8725232
hexc329d9efd11

13411532340497 has 2 divisors, whose sum is σ = 13411532340498. Its totient is φ = 13411532340496.

The previous prime is 13411532340389. The next prime is 13411532340509. The reversal of 13411532340497 is 79404323511431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8839466319376 + 4572066021121 = 2973124^2 + 2138239^2 .

It is an emirp because it is prime and its reverse (79404323511431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13411532340497 is a prime.

It is not a weakly prime, because it can be changed into another prime (13411532340197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705766170248 + 6705766170249.

It is an arithmetic number, because the mean of its divisors is an integer number (6705766170249).

Almost surely, 213411532340497 is an apocalyptic number.

It is an amenable number.

13411532340497 is a deficient number, since it is larger than the sum of its proper divisors (1).

13411532340497 is an equidigital number, since it uses as much as digits as its factorization.

13411532340497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1088640, while the sum is 47.

The spelling of 13411532340497 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty-two million, three hundred forty thousand, four hundred ninety-seven".