Base | Representation |
---|---|
bin | 1100001100101001110110… |
… | …1110100101101101011011 |
3 | 1202111010111212120121202102 |
4 | 3003022131232211231123 |
5 | 3224213310214242412 |
6 | 44305101305154015 |
7 | 2552644214126504 |
oct | 303123556455533 |
9 | 52433455517672 |
10 | 13411534134107 |
11 | 430088842082a |
12 | 16072b378b90b |
13 | 763918a97a85 |
14 | 34519bdb7bab |
15 | 183ce897b8c2 |
hex | c329dba5b5b |
13411534134107 has 2 divisors, whose sum is σ = 13411534134108. Its totient is φ = 13411534134106.
The previous prime is 13411534134073. The next prime is 13411534134133. The reversal of 13411534134107 is 70143143511431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13411534134107 - 210 = 13411534133083 is a prime.
It is a super-3 number, since 3×134115341341073 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13411534134137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705767067053 + 6705767067054.
It is an arithmetic number, because the mean of its divisors is an integer number (6705767067054).
Almost surely, 213411534134107 is an apocalyptic number.
13411534134107 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411534134107 is an equidigital number, since it uses as much as digits as its factorization.
13411534134107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 38.
Adding to 13411534134107 its reverse (70143143511431), we get a palindrome (83554677645538).
The spelling of 13411534134107 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty-four million, one hundred thirty-four thousand, one hundred seven".
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