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13411534134107 is a prime number
BaseRepresentation
bin1100001100101001110110…
…1110100101101101011011
31202111010111212120121202102
43003022131232211231123
53224213310214242412
644305101305154015
72552644214126504
oct303123556455533
952433455517672
1013411534134107
11430088842082a
1216072b378b90b
13763918a97a85
1434519bdb7bab
15183ce897b8c2
hexc329dba5b5b

13411534134107 has 2 divisors, whose sum is σ = 13411534134108. Its totient is φ = 13411534134106.

The previous prime is 13411534134073. The next prime is 13411534134133. The reversal of 13411534134107 is 70143143511431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13411534134107 - 210 = 13411534133083 is a prime.

It is a super-3 number, since 3×134115341341073 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13411534134137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705767067053 + 6705767067054.

It is an arithmetic number, because the mean of its divisors is an integer number (6705767067054).

Almost surely, 213411534134107 is an apocalyptic number.

13411534134107 is a deficient number, since it is larger than the sum of its proper divisors (1).

13411534134107 is an equidigital number, since it uses as much as digits as its factorization.

13411534134107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 38.

Adding to 13411534134107 its reverse (70143143511431), we get a palindrome (83554677645538).

The spelling of 13411534134107 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty-four million, one hundred thirty-four thousand, one hundred seven".