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134121143222273 is a prime number
BaseRepresentation
bin11110011111101110000011…
…000110010100000000000001
3122120212212010002001022100002
4132133232003012110000001
5120034420100131103043
61153130222543405345
740151634650131544
oct3637560306240001
9576785102038302
10134121143222273
113980a5038aa809
12130616ab5b3855
1359ab75337005c
1425196d85d485b
151078beaa7bbb8
hex79fb83194001

134121143222273 has 2 divisors, whose sum is σ = 134121143222274. Its totient is φ = 134121143222272.

The previous prime is 134121143222237. The next prime is 134121143222359. The reversal of 134121143222273 is 372222341121431.

Together with previous prime (134121143222237) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124363691511409 + 9757451710864 = 11151847^2 + 3123692^2 .

It is a cyclic number.

It is not a de Polignac number, because 134121143222273 - 212 = 134121143218177 is a prime.

It is not a weakly prime, because it can be changed into another prime (134121143222203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67060571611136 + 67060571611137.

It is an arithmetic number, because the mean of its divisors is an integer number (67060571611137).

Almost surely, 2134121143222273 is an apocalyptic number.

It is an amenable number.

134121143222273 is a deficient number, since it is larger than the sum of its proper divisors (1).

134121143222273 is an equidigital number, since it uses as much as digits as its factorization.

134121143222273 is an evil number, because the sum of its binary digits is even.

The product of its digits is 96768, while the sum is 38.

The spelling of 134121143222273 in words is "one hundred thirty-four trillion, one hundred twenty-one billion, one hundred forty-three million, two hundred twenty-two thousand, two hundred seventy-three".