Base | Representation |
---|---|
bin | 11000111110110111… |
… | …00110100010111001 |
3 | 1021121201110221120101 |
4 | 30133123212202321 |
5 | 204432012400403 |
6 | 10054514355401 |
7 | 653240041213 |
oct | 143733464271 |
9 | 37551427511 |
10 | 13412231353 |
11 | 5762944a24 |
12 | 272388bb61 |
13 | 1359906691 |
14 | 9133d55b3 |
15 | 53772e71d |
hex | 31f6e68b9 |
13412231353 has 4 divisors (see below), whose sum is σ = 13416442960. Its totient is φ = 13408019748.
The previous prime is 13412231323. The next prime is 13412231383. The reversal of 13412231353 is 35313221431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35313221431 = 22679 ⋅1557089.
It is an interprime number because it is at equal distance from previous prime (13412231323) and next prime (13412231383).
It is a cyclic number.
It is not a de Polignac number, because 13412231353 - 221 = 13410134201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13412231323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2101023 + ... + 2107396.
It is an arithmetic number, because the mean of its divisors is an integer number (3354110740).
Almost surely, 213412231353 is an apocalyptic number.
It is an amenable number.
13412231353 is a deficient number, since it is larger than the sum of its proper divisors (4211607).
13412231353 is an equidigital number, since it uses as much as digits as its factorization.
13412231353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4211606.
The product of its digits is 6480, while the sum is 28.
Adding to 13412231353 its reverse (35313221431), we get a palindrome (48725452784).
The spelling of 13412231353 in words is "thirteen billion, four hundred twelve million, two hundred thirty-one thousand, three hundred fifty-three".
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