13412486705643 has 12 divisors (see below), whose sum is σ = 19454652965280. Its totient is φ = 8904245008176.

The previous prime is 13412486705623. The next prime is 13412486705669. The reversal of 13412486705643 is 34650768421431.

13412486705643 is a `hidden beast` number, since 1 + 3 + 4 + 1 + 2 + 4 + 8 + 6 + 70 + 564 + 3 = 666.

13412486705643 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13412486705643 - 2¹⁶ = 13412486640107 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13412486705643.

It is not an unprimeable number, because it can be changed into a prime (13412486705603) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3117730696 + ... + 3117734997.

It is an arithmetic number, because the mean of its divisors is an integer number (1621221080440).

Almost surely, 2^{13412486705643} is an apocalyptic number.

13412486705643 is a deficient number, since it is larger than the sum of its proper divisors (6042166259637).

13412486705643 is a wasteful number, since it uses less digits than its factorization.

13412486705643 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6235465938 (or 6235465935 counting only the distinct ones).

The product of its (nonzero) digits is 11612160, while the sum is 54.

The spelling of 13412486705643 in words is "thirteen trillion, four hundred twelve billion, four hundred eighty-six million, seven hundred five thousand, six hundred forty-three".