134125220654443 has 2 divisors, whose sum is σ = 134125220654444. Its totient is φ = 134125220654442.

The previous prime is 134125220654401. The next prime is 134125220654483. The reversal of 134125220654443 is 344456022521431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134125220654443 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134125220654393 and 134125220654402.

It is not a weakly prime, because it can be changed into another prime (134125220654483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67062610327221 + 67062610327222.

It is an arithmetic number, because the mean of its divisors is an integer number (67062610327222).

Almost surely, 2^{134125220654443} is an apocalyptic number.

134125220654443 is a deficient number, since it is larger than the sum of its proper divisors (1).

134125220654443 is an equidigital number, since it uses as much as digits as its factorization.

134125220654443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2764800, while the sum is 46.

The spelling of 134125220654443 in words is "one hundred thirty-four trillion, one hundred twenty-five billion, two hundred twenty million, six hundred fifty-four thousand, four hundred forty-three".