13413250645411 has 4 divisors (see below), whose sum is σ = 13416838039000. Its totient is φ = 13409663251824.

The previous prime is 13413250645397. The next prime is 13413250645427. The reversal of 13413250645411 is 11454605231431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13413250645411 - 2¹⁹ = 13413250121123 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13413250645211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1793691186 + ... + 1793698663.

It is an arithmetic number, because the mean of its divisors is an integer number (3354209509750).

Almost surely, 2^{13413250645411} is an apocalyptic number.

13413250645411 is a deficient number, since it is larger than the sum of its proper divisors (3587393589).

13413250645411 is an equidigital number, since it uses as much as digits as its factorization.

13413250645411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3587393588.

The product of its (nonzero) digits is 172800, while the sum is 40.

Adding to 13413250645411 its reverse (11454605231431), we get a palindrome (24867855876842).

The spelling of 13413250645411 in words is "thirteen trillion, four hundred thirteen billion, two hundred fifty million, six hundred forty-five thousand, four hundred eleven".