Base | Representation |
---|---|
bin | 1100001100110000010000… |
… | …0111110001110110001011 |
3 | 1202111021221121001221012022 |
4 | 3003030010013301312023 |
5 | 3224230320003412301 |
6 | 44305543553235055 |
7 | 2553034613636213 |
oct | 303140407616613 |
9 | 52437847057168 |
10 | 13413252013451 |
11 | 430158a095a24 |
12 | 16076b2b62a8b |
13 | 763b30964424 |
14 | 3452c21d5243 |
15 | 183d996b2d1b |
hex | c33041f1d8b |
13413252013451 has 4 divisors (see below), whose sum is σ = 13845937562304. Its totient is φ = 12980566464600.
The previous prime is 13413252013429. The next prime is 13413252013487. The reversal of 13413252013451 is 15431025231431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13413252013451 - 218 = 13413251751307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13413252033451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216342774380 + ... + 216342774441.
It is an arithmetic number, because the mean of its divisors is an integer number (3461484390576).
Almost surely, 213413252013451 is an apocalyptic number.
13413252013451 is a deficient number, since it is larger than the sum of its proper divisors (432685548853).
13413252013451 is an equidigital number, since it uses as much as digits as its factorization.
13413252013451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 432685548852.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 13413252013451 its reverse (15431025231431), we get a palindrome (28844277244882).
The spelling of 13413252013451 in words is "thirteen trillion, four hundred thirteen billion, two hundred fifty-two million, thirteen thousand, four hundred fifty-one".
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