Base | Representation |
---|---|
bin | 11000111110111111… |
… | …01100001101010001 |
3 | 1021121210111101202111 |
4 | 30133133230031101 |
5 | 204432301144441 |
6 | 10054553345321 |
7 | 653252124001 |
oct | 143737541521 |
9 | 37553441674 |
10 | 13413303121 |
11 | 5763507189 |
12 | 2724108241 |
13 | 1359bc046a |
14 | 9135d4001 |
15 | 537892081 |
hex | 31f7ec351 |
13413303121 has 2 divisors, whose sum is σ = 13413303122. Its totient is φ = 13413303120.
The previous prime is 13413303109. The next prime is 13413303131. The reversal of 13413303121 is 12130331431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11403036225 + 2010266896 = 106785^2 + 44836^2 .
It is an emirp because it is prime and its reverse (12130331431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13413303121 - 211 = 13413301073 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13413303092 and 13413303101.
It is not a weakly prime, because it can be changed into another prime (13413303131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706651560 + 6706651561.
It is an arithmetic number, because the mean of its divisors is an integer number (6706651561).
Almost surely, 213413303121 is an apocalyptic number.
It is an amenable number.
13413303121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13413303121 is an equidigital number, since it uses as much as digits as its factorization.
13413303121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 13413303121 its reverse (12130331431), we get a palindrome (25543634552).
The spelling of 13413303121 in words is "thirteen billion, four hundred thirteen million, three hundred three thousand, one hundred twenty-one".
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