1341411101441 has 4 divisors (see below), whose sum is σ = 1377665455572. Its totient is φ = 1305156747312.

The previous prime is 1341411101431. The next prime is 1341411101461. The reversal of 1341411101441 is 1441011141431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1110064531216 + 231346570225 = 1053596^2 + 480985^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1341411101441 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1341411101441.

It is not an unprimeable number, because it can be changed into a prime (1341411101431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18127177010 + ... + 18127177083.

It is an arithmetic number, because the mean of its divisors is an integer number (344416363893).

Almost surely, 2^{1341411101441} is an apocalyptic number.

It is an amenable number.

1341411101441 is a deficient number, since it is larger than the sum of its proper divisors (36254354131).

1341411101441 is an equidigital number, since it uses as much as digits as its factorization.

1341411101441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36254354130.

The product of its (nonzero) digits is 768, while the sum is 26.

Adding to 1341411101441 its reverse (1441011141431), we get a palindrome (2782422242872).

The spelling of 1341411101441 in words is "one trillion, three hundred forty-one billion, four hundred eleven million, one hundred one thousand, four hundred forty-one".