Base | Representation |
---|---|
bin | 1100001100110011011111… |
… | …1011010000010010100001 |
3 | 1202111101012011111102020101 |
4 | 3003030313323100102201 |
5 | 3224234110003124010 |
6 | 44310210121542401 |
7 | 2553065266303003 |
oct | 303146773202241 |
9 | 52441164442211 |
10 | 13414121145505 |
11 | 4301995754783 |
12 | 16078b6044a01 |
13 | 763c3ba40a52 |
14 | 3453657d8373 |
15 | 183deab4373a |
hex | c3337ed04a1 |
13414121145505 has 16 divisors (see below), whose sum is σ = 16319633657040. Its totient is φ = 10582877380608.
The previous prime is 13414121145499. The next prime is 13414121145517. The reversal of 13414121145505 is 50554112141431.
It can be written as a sum of positive squares in 8 ways, for example, as 1834093278369 + 11580027867136 = 1354287^2 + 3402944^2 .
It is a cyclic number.
It is not a de Polignac number, because 13414121145505 - 25 = 13414121145473 is a prime.
It is a super-2 number, since 2×134141211455052 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 279819 + ... + 5187151.
It is an arithmetic number, because the mean of its divisors is an integer number (1019977103565).
Almost surely, 213414121145505 is an apocalyptic number.
It is an amenable number.
13414121145505 is a deficient number, since it is larger than the sum of its proper divisors (2905512511535).
13414121145505 is an equidigital number, since it uses as much as digits as its factorization.
13414121145505 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4914900.
The product of its (nonzero) digits is 48000, while the sum is 37.
Adding to 13414121145505 its reverse (50554112141431), we get a palindrome (63968233286936).
The spelling of 13414121145505 in words is "thirteen trillion, four hundred fourteen billion, one hundred twenty-one million, one hundred forty-five thousand, five hundred five".
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