Base | Representation |
---|---|
bin | 100111111110100… |
… | …1001110111001001 |
3 | 10110111010202201120 |
4 | 1033331021313021 |
5 | 10221401244431 |
6 | 341035305453 |
7 | 45145656153 |
oct | 11775116711 |
9 | 3414122646 |
10 | 1341431241 |
11 | 629226167 |
12 | 3152ab289 |
13 | 184bb30c7 |
14 | ca227ad3 |
15 | 7cb76196 |
hex | 4ff49dc9 |
1341431241 has 4 divisors (see below), whose sum is σ = 1788574992. Its totient is φ = 894287492.
The previous prime is 1341431239. The next prime is 1341431327. The reversal of 1341431241 is 1421341431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1341431241 - 21 = 1341431239 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1341430241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223571871 + ... + 223571876.
It is an arithmetic number, because the mean of its divisors is an integer number (447143748).
Almost surely, 21341431241 is an apocalyptic number.
It is an amenable number.
1341431241 is a deficient number, since it is larger than the sum of its proper divisors (447143751).
1341431241 is an equidigital number, since it uses as much as digits as its factorization.
1341431241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 447143750.
The product of its digits is 1152, while the sum is 24.
The square root of 1341431241 is about 36625.5544804444. The cubic root of 1341431241 is about 1102.8661456324.
Adding to 1341431241 its reverse (1421341431), we get a palindrome (2762772672).
The spelling of 1341431241 in words is "one billion, three hundred forty-one million, four hundred thirty-one thousand, two hundred forty-one".
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