Base | Representation |
---|---|
bin | 11000111111000111… |
… | …11011001110111001 |
3 | 1021121212120210120001 |
4 | 30133203323032321 |
5 | 204433042210431 |
6 | 10055033233001 |
7 | 653264426335 |
oct | 143743731671 |
9 | 37555523501 |
10 | 13414413241 |
11 | 57640a5239 |
12 | 2724562761 |
13 | 135a1bb838 |
14 | 9138027c5 |
15 | 537a10e61 |
hex | 31f8fb3b9 |
13414413241 has 4 divisors (see below), whose sum is σ = 13614628432. Its totient is φ = 13214198052.
The previous prime is 13414413223. The next prime is 13414413277. The reversal of 13414413241 is 14231441431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13414413241 - 213 = 13414405049 is a prime.
It is a super-2 number, since 2×134144132412 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13414413541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100107495 + ... + 100107628.
It is an arithmetic number, because the mean of its divisors is an integer number (3403657108).
Almost surely, 213414413241 is an apocalyptic number.
It is an amenable number.
13414413241 is a deficient number, since it is larger than the sum of its proper divisors (200215191).
13414413241 is an equidigital number, since it uses as much as digits as its factorization.
13414413241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 200215190.
The product of its digits is 4608, while the sum is 28.
Adding to 13414413241 its reverse (14231441431), we get a palindrome (27645854672).
The spelling of 13414413241 in words is "thirteen billion, four hundred fourteen million, four hundred thirteen thousand, two hundred forty-one".
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