13414421253401 has 12 divisors (see below), whose sum is σ = 15641596263780. Its totient is φ = 11470763999520.

The previous prime is 13414421253391. The next prime is 13414421253407. The reversal of 13414421253401 is 10435212441431.

It can be written as a sum of positive squares in 2 ways, for example, as 16266451600 + 13398154801801 = 127540^2 + 3660349^2 .

It is not a de Polignac number, because 13414421253401 - 2²² = 13414417059097 is a prime.

It is a super-3 number, since 3×13414421253401³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13414421253407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 325114406 + ... + 325155663.

It is an arithmetic number, because the mean of its divisors is an integer number (1303466355315).

Almost surely, 2^{13414421253401} is an apocalyptic number.

It is an amenable number.

13414421253401 is a deficient number, since it is larger than the sum of its proper divisors (2227175010379).

13414421253401 is an equidigital number, since it uses as much as digits as its factorization.

13414421253401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 650270504 (or 650270497 counting only the distinct ones).

The product of its (nonzero) digits is 46080, while the sum is 35.

Adding to 13414421253401 its reverse (10435212441431), we get a palindrome (23849633694832).

The spelling of 13414421253401 in words is "thirteen trillion, four hundred fourteen billion, four hundred twenty-one million, two hundred fifty-three thousand, four hundred one".