Base | Representation |
---|---|
bin | 10011100001010100110… |
… | …101110111110001000011 |
3 | 11202020112011212102121021 |
4 | 103201110311313301003 |
5 | 133434244010021142 |
6 | 2504131033410311 |
7 | 165626314050211 |
oct | 23412465676103 |
9 | 4666464772537 |
10 | 1341453204547 |
11 | 4779a83a9325 |
12 | 197b95b69997 |
13 | 99663266341 |
14 | 48cd8b57cb1 |
15 | 24d632b1267 |
hex | 13854d77c43 |
1341453204547 has 2 divisors, whose sum is σ = 1341453204548. Its totient is φ = 1341453204546.
The previous prime is 1341453204433. The next prime is 1341453204551. The reversal of 1341453204547 is 7454023541431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1341453204547 - 235 = 1307093466179 is a prime.
It is not a weakly prime, because it can be changed into another prime (1341453204557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670726602273 + 670726602274.
It is an arithmetic number, because the mean of its divisors is an integer number (670726602274).
Almost surely, 21341453204547 is an apocalyptic number.
1341453204547 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341453204547 is an equidigital number, since it uses as much as digits as its factorization.
1341453204547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 806400, while the sum is 43.
Adding to 1341453204547 its reverse (7454023541431), we get a palindrome (8795476745978).
The spelling of 1341453204547 in words is "one trillion, three hundred forty-one billion, four hundred fifty-three million, two hundred four thousand, five hundred forty-seven".
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