Base | Representation |
---|---|
bin | 11000111111001011… |
… | …10011001010100011 |
3 | 1021121220111202102012 |
4 | 30133211303022203 |
5 | 204433203420413 |
6 | 10055051543135 |
7 | 653301543461 |
oct | 143745631243 |
9 | 37556452365 |
10 | 13414904483 |
11 | 5764400322 |
12 | 272475aaab |
13 | 135a331306 |
14 | 9138cd831 |
15 | 537aab7a8 |
hex | 31f9732a3 |
13414904483 has 2 divisors, whose sum is σ = 13414904484. Its totient is φ = 13414904482.
The previous prime is 13414904467. The next prime is 13414904509. The reversal of 13414904483 is 38440941431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13414904483 - 24 = 13414904467 is a prime.
It is a super-3 number, since 3×134149044833 (a number of 31 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13414904483.
It is not a weakly prime, because it can be changed into another prime (13414904683) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707452241 + 6707452242.
It is an arithmetic number, because the mean of its divisors is an integer number (6707452242).
Almost surely, 213414904483 is an apocalyptic number.
13414904483 is a deficient number, since it is larger than the sum of its proper divisors (1).
13414904483 is an equidigital number, since it uses as much as digits as its factorization.
13414904483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 165888, while the sum is 41.
The spelling of 13414904483 in words is "thirteen billion, four hundred fourteen million, nine hundred four thousand, four hundred eighty-three".
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