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13420404034003 is a prime number
BaseRepresentation
bin1100001101001010111001…
…1010100100100111010011
31202111222102000212012222101
43003102232122210213103
53224334441413042003
644313125402021231
72553410060052121
oct303225632444723
952458360765871
1013420404034003
11430461a23190a
121608b6a1a7817
137647005c5b55
143457a0004911
1518416750a11d
hexc34ae6a49d3

13420404034003 has 2 divisors, whose sum is σ = 13420404034004. Its totient is φ = 13420404034002.

The previous prime is 13420404033989. The next prime is 13420404034057. The reversal of 13420404034003 is 30043040402431.

13420404034003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13420404034003 - 229 = 13419867163091 is a prime.

It is not a weakly prime, because it can be changed into another prime (13420404034073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710202017001 + 6710202017002.

It is an arithmetic number, because the mean of its divisors is an integer number (6710202017002).

Almost surely, 213420404034003 is an apocalyptic number.

13420404034003 is a deficient number, since it is larger than the sum of its proper divisors (1).

13420404034003 is an equidigital number, since it uses as much as digits as its factorization.

13420404034003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 13420404034003 its reverse (30043040402431), we get a palindrome (43463444436434).

The spelling of 13420404034003 in words is "thirteen trillion, four hundred twenty billion, four hundred four million, thirty-four thousand, three".