Base | Representation |
---|---|
bin | 111110011111110001… |
… | …0111100110111101011 |
3 | 110211102100000010221001 |
4 | 1330333202330313223 |
5 | 4144330242104003 |
6 | 141353312255431 |
7 | 12460565065201 |
oct | 1747742746753 |
9 | 424370003831 |
10 | 134210113003 |
11 | 51a1112336a |
12 | 22016841577 |
13 | c86b1b1665 |
14 | 66d26b5071 |
15 | 375778e61d |
hex | 1f3f8bcdeb |
134210113003 has 4 divisors (see below), whose sum is σ = 134210935440. Its totient is φ = 134209290568.
The previous prime is 134210113001. The next prime is 134210113013. The reversal of 134210113003 is 300311012431.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 300311012431 = 356101 ⋅843331.
It is a cyclic number.
It is not a de Polignac number, because 134210113003 - 21 = 134210113001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134210113001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74575 + ... + 523432.
It is an arithmetic number, because the mean of its divisors is an integer number (33552733860).
Almost surely, 2134210113003 is an apocalyptic number.
134210113003 is a deficient number, since it is larger than the sum of its proper divisors (822437).
134210113003 is an equidigital number, since it uses as much as digits as its factorization.
134210113003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 822436.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 134210113003 its reverse (300311012431), we get a palindrome (434521125434).
The spelling of 134210113003 in words is "one hundred thirty-four billion, two hundred ten million, one hundred thirteen thousand, three".
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