Base | Representation |
---|---|
bin | 1100001101001101110111… |
… | …1101111001110111110011 |
3 | 1202112001110122001012211222 |
4 | 3003103131331321313303 |
5 | 3224343110131402032 |
6 | 44313340501255255 |
7 | 2553435615136145 |
oct | 303233575716763 |
9 | 52461418035758 |
10 | 13421201825267 |
11 | 43049995a4235 |
12 | 160915140452b |
13 | 7647c99845a2 |
14 | 345837d56c95 |
15 | 1841b2597a12 |
hex | c34ddf79df3 |
13421201825267 has 2 divisors, whose sum is σ = 13421201825268. Its totient is φ = 13421201825266.
The previous prime is 13421201825159. The next prime is 13421201825309. The reversal of 13421201825267 is 76252810212431.
It is a strong prime.
It is an emirp because it is prime and its reverse (76252810212431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13421201825267 - 28 = 13421201825011 is a prime.
It is not a weakly prime, because it can be changed into another prime (13421201825567) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710600912633 + 6710600912634.
It is an arithmetic number, because the mean of its divisors is an integer number (6710600912634).
Almost surely, 213421201825267 is an apocalyptic number.
13421201825267 is a deficient number, since it is larger than the sum of its proper divisors (1).
13421201825267 is an equidigital number, since it uses as much as digits as its factorization.
13421201825267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 322560, while the sum is 44.
The spelling of 13421201825267 in words is "thirteen trillion, four hundred twenty-one billion, two hundred one million, eight hundred twenty-five thousand, two hundred sixty-seven".
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