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134212452307 is a prime number
BaseRepresentation
bin111110011111110101…
…1110111111111010011
3110211102111101222211221
41330333223313333103
54144331341433212
6141353434345511
712460624010263
oct1747753677723
9424374358757
10134212452307
1151a1248097a
122201758b297
13c86b82036b
1466d2b237a3
153757aa2807
hex1f3faf7fd3

134212452307 has 2 divisors, whose sum is σ = 134212452308. Its totient is φ = 134212452306.

The previous prime is 134212452287. The next prime is 134212452317. The reversal of 134212452307 is 703254212431.

It is a strong prime.

It is an emirp because it is prime and its reverse (703254212431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134212452307 is a prime.

It is not a weakly prime, because it can be changed into another prime (134212452317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67106226153 + 67106226154.

It is an arithmetic number, because the mean of its divisors is an integer number (67106226154).

Almost surely, 2134212452307 is an apocalyptic number.

134212452307 is a deficient number, since it is larger than the sum of its proper divisors (1).

134212452307 is an equidigital number, since it uses as much as digits as its factorization.

134212452307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40320, while the sum is 34.

Adding to 134212452307 its reverse (703254212431), we get a palindrome (837466664738).

The spelling of 134212452307 in words is "one hundred thirty-four billion, two hundred twelve million, four hundred fifty-two thousand, three hundred seven".