1342132010113 has 4 divisors (see below), whose sum is σ = 1342134441648. Its totient is φ = 1342129578580.

The previous prime is 1342132010083. The next prime is 1342132010119. The reversal of 1342132010113 is 3110102312431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1342132010113 - 2⁹ = 1342132009601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1342132010119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54798 + ... + 1639288.

It is an arithmetic number, because the mean of its divisors is an integer number (335533610412).

Almost surely, 2^{1342132010113} is an apocalyptic number.

It is an amenable number.

1342132010113 is a deficient number, since it is larger than the sum of its proper divisors (2431535).

1342132010113 is an equidigital number, since it uses as much as digits as its factorization.

1342132010113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2431534.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1342132010113 its reverse (3110102312431), we get a palindrome (4452234322544).

The spelling of 1342132010113 in words is "one trillion, three hundred forty-two billion, one hundred thirty-two million, ten thousand, one hundred thirteen".