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13421401321043 is a prime number
BaseRepresentation
bin1100001101001110100111…
…0110111010111001010011
31202112001222112102122121102
43003103221312322321103
53224344012214233133
644313412345215015
72553443556623402
oct303235166727123
952461875378542
1013421401321043
114304a91172381
1216091a819146b
1376482c0c3221
14345856647639
151841c4d527e8
hexc34e9dbae53

13421401321043 has 2 divisors, whose sum is σ = 13421401321044. Its totient is φ = 13421401321042.

The previous prime is 13421401321021. The next prime is 13421401321093. The reversal of 13421401321043 is 34012310412431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13421401321043 - 214 = 13421401304659 is a prime.

It is a super-3 number, since 3×134214013210433 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13421401320997 and 13421401321015.

It is not a weakly prime, because it can be changed into another prime (13421401321093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710700660521 + 6710700660522.

It is an arithmetic number, because the mean of its divisors is an integer number (6710700660522).

Almost surely, 213421401321043 is an apocalyptic number.

13421401321043 is a deficient number, since it is larger than the sum of its proper divisors (1).

13421401321043 is an equidigital number, since it uses as much as digits as its factorization.

13421401321043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13421401321043 its reverse (34012310412431), we get a palindrome (47433711733474).

The spelling of 13421401321043 in words is "thirteen trillion, four hundred twenty-one billion, four hundred one million, three hundred twenty-one thousand, forty-three".