Base | Representation |
---|---|
bin | 11110100001000100101001… |
… | …000010000000000011000011 |
3 | 122121012202002212221021212122 |
4 | 132201010221002000003003 |
5 | 120042431010041014133 |
6 | 1153241041033114455 |
7 | 40161436021606304 |
oct | 3641045102000303 |
9 | 577182085837778 |
10 | 134214121423043 |
11 | 39845986652152 |
12 | 13077719858a2b |
13 | 59b74501b34bc |
14 | 251ddd8c627ab |
15 | 107b33d5e3498 |
hex | 7a11290800c3 |
134214121423043 has 2 divisors, whose sum is σ = 134214121423044. Its totient is φ = 134214121423042.
The previous prime is 134214121423027. The next prime is 134214121423049. The reversal of 134214121423043 is 340324121412431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134214121423043 - 24 = 134214121423027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134214121422994 and 134214121423012.
It is not a weakly prime, because it can be changed into another prime (134214121423049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67107060711521 + 67107060711522.
It is an arithmetic number, because the mean of its divisors is an integer number (67107060711522).
Almost surely, 2134214121423043 is an apocalyptic number.
134214121423043 is a deficient number, since it is larger than the sum of its proper divisors (1).
134214121423043 is an equidigital number, since it uses as much as digits as its factorization.
134214121423043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 134214121423043 its reverse (340324121412431), we get a palindrome (474538242835474).
The spelling of 134214121423043 in words is "one hundred thirty-four trillion, two hundred fourteen billion, one hundred twenty-one million, four hundred twenty-three thousand, forty-three".
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