Base | Representation |
---|---|
bin | 1100001101001111101110… |
… | …1010010110010011011011 |
3 | 1202112002202100110220010112 |
4 | 3003103323222112103123 |
5 | 3224400120200442243 |
6 | 44313502135234535 |
7 | 2553454144524245 |
oct | 303237352262333 |
9 | 52462670426115 |
10 | 13421700015323 |
11 | 4305124834856 |
12 | 1609270218a4b |
13 | 764878c548c2 |
14 | 34588419b095 |
15 | 1841e11a4818 |
hex | c34fba964db |
13421700015323 has 2 divisors, whose sum is σ = 13421700015324. Its totient is φ = 13421700015322.
The previous prime is 13421700015307. The next prime is 13421700015377. The reversal of 13421700015323 is 32351000712431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13421700015323 - 24 = 13421700015307 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13421700015323.
It is not a weakly prime, because it can be changed into another prime (13421700015023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710850007661 + 6710850007662.
It is an arithmetic number, because the mean of its divisors is an integer number (6710850007662).
Almost surely, 213421700015323 is an apocalyptic number.
13421700015323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13421700015323 is an equidigital number, since it uses as much as digits as its factorization.
13421700015323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 13421700015323 its reverse (32351000712431), we get a palindrome (45772700727754).
The spelling of 13421700015323 in words is "thirteen trillion, four hundred twenty-one billion, seven hundred million, fifteen thousand, three hundred twenty-three".
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