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13422343331 = 47285581773
BaseRepresentation
bin11001000000000100…
…01011010010100011
31021122102111200121002
430200002023102203
5204442104441311
610055515222215
7653422015205
oct144002132243
937572450532
1013422343331
115768621231
12272714796b
13135ba371b7
149148a8775
1553857a93b
hex32008b4a3

13422343331 has 4 divisors (see below), whose sum is σ = 13707925152. Its totient is φ = 13136761512.

The previous prime is 13422343321. The next prime is 13422343349. The reversal of 13422343331 is 13334322431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13334322431 = 41393221629.

It is a cyclic number.

It is not a de Polignac number, because 13422343331 - 226 = 13355234467 is a prime.

It is a super-2 number, since 2×134223433312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13422343294 and 13422343303.

It is not an unprimeable number, because it can be changed into a prime (13422343321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142790840 + ... + 142790933.

It is an arithmetic number, because the mean of its divisors is an integer number (3426981288).

Almost surely, 213422343331 is an apocalyptic number.

13422343331 is a deficient number, since it is larger than the sum of its proper divisors (285581821).

13422343331 is an equidigital number, since it uses as much as digits as its factorization.

13422343331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 285581820.

The product of its digits is 15552, while the sum is 29.

Adding to 13422343331 its reverse (13334322431), we get a palindrome (26756665762).

The spelling of 13422343331 in words is "thirteen billion, four hundred twenty-two million, three hundred forty-three thousand, three hundred thirty-one".

Divisors: 1 47 285581773 13422343331