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1342260536443 = 1710778462649
BaseRepresentation
bin10011100010000100111…
…101100110010001111011
311202022121110000010202121
4103202010331212101323
5133442422144131233
62504343113342111
7165655316211421
oct23420475462173
94668543003677
101342260536443
11478282097772
12198180407937
13997615b5518
1448d74071111
1524dae0d592d
hex13884f6647b

1342260536443 has 4 divisors (see below), whose sum is σ = 1342339016200. Its totient is φ = 1342182056688.

The previous prime is 1342260536423. The next prime is 1342260536471. The reversal of 1342260536443 is 3446350622431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1342260536443 - 237 = 1204821582971 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1342260536443.

It is not an unprimeable number, because it can be changed into a prime (1342260536413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39214218 + ... + 39248431.

It is an arithmetic number, because the mean of its divisors is an integer number (335584754050).

Almost surely, 21342260536443 is an apocalyptic number.

1342260536443 is a deficient number, since it is larger than the sum of its proper divisors (78479757).

1342260536443 is an equidigital number, since it uses as much as digits as its factorization.

1342260536443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 78479756.

The product of its (nonzero) digits is 1244160, while the sum is 43.

The spelling of 1342260536443 in words is "one trillion, three hundred forty-two billion, two hundred sixty million, five hundred thirty-six thousand, four hundred forty-three".

Divisors: 1 17107 78462649 1342260536443