Search a number
-
+
1342300165321 = 2593951748339
BaseRepresentation
bin10011100010000111010…
…100110001010011001001
311202022201012120111100211
4103202013110301103021
5133443012320242241
62504351051001121
7165656310102463
oct23420724612311
94668635514324
101342300165321
114782a24a4505
121981917391a1
139976987c16b
1448d79429133
1524db2812781
hex138875314c9

1342300165321 has 4 divisors (see below), whose sum is σ = 1342351939600. Its totient is φ = 1342248391044.

The previous prime is 1342300165291. The next prime is 1342300165333. The reversal of 1342300165321 is 1235610032431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1342300165321 - 221 = 1342298068169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1342300165351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25848231 + ... + 25900108.

It is an arithmetic number, because the mean of its divisors is an integer number (335587984900).

Almost surely, 21342300165321 is an apocalyptic number.

It is an amenable number.

1342300165321 is a deficient number, since it is larger than the sum of its proper divisors (51774279).

1342300165321 is an equidigital number, since it uses as much as digits as its factorization.

1342300165321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51774278.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 1342300165321 its reverse (1235610032431), we get a palindrome (2577910197752).

The spelling of 1342300165321 in words is "one trillion, three hundred forty-two billion, three hundred million, one hundred sixty-five thousand, three hundred twenty-one".

Divisors: 1 25939 51748339 1342300165321