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13423504512001 = 71189063443831
BaseRepresentation
bin1100001101010110011100…
…1101111101010000000001
31202112021102002221211012211
43003111213031331100001
53224412314123341001
644314401200022121
72553546645510433
oct303254715752001
952467362854184
1013423504512001
11430597038a921
121609694601941
13764aa5a5a60c
143459b5ac4653
151842997ea351
hexc356737d401

13423504512001 has 4 divisors (see below), whose sum is σ = 13612567955904. Its totient is φ = 13234441068100.

The previous prime is 13423504511981. The next prime is 13423504512029. The reversal of 13423504512001 is 10021540532431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13423504512001 - 217 = 13423504380929 is a prime.

It is a super-2 number, since 2×134235045120012 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13423504542001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94531721845 + ... + 94531721986.

It is an arithmetic number, because the mean of its divisors is an integer number (3403141988976).

Almost surely, 213423504512001 is an apocalyptic number.

It is an amenable number.

13423504512001 is a deficient number, since it is larger than the sum of its proper divisors (189063443903).

13423504512001 is an equidigital number, since it uses as much as digits as its factorization.

13423504512001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 189063443902.

The product of its (nonzero) digits is 14400, while the sum is 31.

The spelling of 13423504512001 in words is "thirteen trillion, four hundred twenty-three billion, five hundred four million, five hundred twelve thousand, one".

Divisors: 1 71 189063443831 13423504512001