Base | Representation |
---|---|
bin | 11001000000001110… |
… | …01011110001110001 |
3 | 1021122111222101022021 |
4 | 30200013023301301 |
5 | 204442423443144 |
6 | 10100003311441 |
7 | 653436123316 |
oct | 144007136161 |
9 | 37574871267 |
10 | 13423656049 |
11 | 5769338521 |
12 | 272767b581 |
13 | 135c0a685b |
14 | 914b2ad0d |
15 | 538739884 |
hex | 3201cbc71 |
13423656049 has 2 divisors, whose sum is σ = 13423656050. Its totient is φ = 13423656048.
The previous prime is 13423656017. The next prime is 13423656073. The reversal of 13423656049 is 94065632431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13415430625 + 8225424 = 115825^2 + 2868^2 .
It is a cyclic number.
It is not a de Polignac number, because 13423656049 - 25 = 13423656017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13423655996 and 13423656014.
It is not a weakly prime, because it can be changed into another prime (13423656349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711828024 + 6711828025.
It is an arithmetic number, because the mean of its divisors is an integer number (6711828025).
Almost surely, 213423656049 is an apocalyptic number.
It is an amenable number.
13423656049 is a deficient number, since it is larger than the sum of its proper divisors (1).
13423656049 is an equidigital number, since it uses as much as digits as its factorization.
13423656049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 466560, while the sum is 43.
The spelling of 13423656049 in words is "thirteen billion, four hundred twenty-three million, six hundred fifty-six thousand, forty-nine".
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