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134240207693833 is a prime number
BaseRepresentation
bin11110100001011100111011…
…111001001110100000001001
3122121022020102212212011002001
4132201130323321032200021
5120043342421132200313
61153301033340311001
740163351326343023
oct3641347371164011
9577266385764061
10134240207693833
1139855a5267652a
1213080799b42461
1359b9a497a15a7
1425213915b3013
15107bd68838add
hex7a173be4e809

134240207693833 has 2 divisors, whose sum is σ = 134240207693834. Its totient is φ = 134240207693832.

The previous prime is 134240207693777. The next prime is 134240207693849. The reversal of 134240207693833 is 338396702042431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97341349933584 + 36898857760249 = 9866172^2 + 6074443^2 .

It is a cyclic number.

It is not a de Polignac number, because 134240207693833 - 29 = 134240207693321 is a prime.

It is not a weakly prime, because it can be changed into another prime (134240207693863) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67120103846916 + 67120103846917.

It is an arithmetic number, because the mean of its divisors is an integer number (67120103846917).

Almost surely, 2134240207693833 is an apocalyptic number.

It is an amenable number.

134240207693833 is a deficient number, since it is larger than the sum of its proper divisors (1).

134240207693833 is an equidigital number, since it uses as much as digits as its factorization.

134240207693833 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15676416, while the sum is 55.

The spelling of 134240207693833 in words is "one hundred thirty-four trillion, two hundred forty billion, two hundred seven million, six hundred ninety-three thousand, eight hundred thirty-three".