Base | Representation |
---|---|
bin | 11110100001011100111011… |
… | …111001001110100000001001 |
3 | 122121022020102212212011002001 |
4 | 132201130323321032200021 |
5 | 120043342421132200313 |
6 | 1153301033340311001 |
7 | 40163351326343023 |
oct | 3641347371164011 |
9 | 577266385764061 |
10 | 134240207693833 |
11 | 39855a5267652a |
12 | 13080799b42461 |
13 | 59b9a497a15a7 |
14 | 25213915b3013 |
15 | 107bd68838add |
hex | 7a173be4e809 |
134240207693833 has 2 divisors, whose sum is σ = 134240207693834. Its totient is φ = 134240207693832.
The previous prime is 134240207693777. The next prime is 134240207693849. The reversal of 134240207693833 is 338396702042431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 97341349933584 + 36898857760249 = 9866172^2 + 6074443^2 .
It is a cyclic number.
It is not a de Polignac number, because 134240207693833 - 29 = 134240207693321 is a prime.
It is not a weakly prime, because it can be changed into another prime (134240207693863) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67120103846916 + 67120103846917.
It is an arithmetic number, because the mean of its divisors is an integer number (67120103846917).
Almost surely, 2134240207693833 is an apocalyptic number.
It is an amenable number.
134240207693833 is a deficient number, since it is larger than the sum of its proper divisors (1).
134240207693833 is an equidigital number, since it uses as much as digits as its factorization.
134240207693833 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15676416, while the sum is 55.
The spelling of 134240207693833 in words is "one hundred thirty-four trillion, two hundred forty billion, two hundred seven million, six hundred ninety-three thousand, eight hundred thirty-three".
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