Base | Representation |
---|---|
bin | 1100001101011001100110… |
… | …1101000111110001011011 |
3 | 1202112100121010210102102201 |
4 | 3003112121231013301123 |
5 | 3224421032443323423 |
6 | 44315021214511031 |
7 | 2553606642242626 |
oct | 303263155076133 |
9 | 52470533712381 |
10 | 13424351542363 |
11 | 4306265523313 |
12 | 1609890205477 |
13 | 764bac399008 |
14 | 345a563b2dbd |
15 | 1842e8d622ad |
hex | c3599b47c5b |
13424351542363 has 2 divisors, whose sum is σ = 13424351542364. Its totient is φ = 13424351542362.
The previous prime is 13424351542339. The next prime is 13424351542429. The reversal of 13424351542363 is 36324515342431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13424351542363 - 213 = 13424351534171 is a prime.
It is not a weakly prime, because it can be changed into another prime (13424351542333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712175771181 + 6712175771182.
It is an arithmetic number, because the mean of its divisors is an integer number (6712175771182).
Almost surely, 213424351542363 is an apocalyptic number.
13424351542363 is a deficient number, since it is larger than the sum of its proper divisors (1).
13424351542363 is an equidigital number, since it uses as much as digits as its factorization.
13424351542363 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3110400, while the sum is 46.
Adding to 13424351542363 its reverse (36324515342431), we get a palindrome (49748866884794).
The spelling of 13424351542363 in words is "thirteen trillion, four hundred twenty-four billion, three hundred fifty-one million, five hundred forty-two thousand, three hundred sixty-three".
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