Base | Representation |
---|---|
bin | 1100001101011001111001… |
… | …1101110110010111101011 |
3 | 1202112100210201002212211000 |
4 | 3003112132131312113223 |
5 | 3224421213421100003 |
6 | 44315033151010043 |
7 | 2553611632236624 |
oct | 303263635662753 |
9 | 52470721085730 |
10 | 13424431425003 |
11 | 43062a6624325 |
12 | 16098b2b09923 |
13 | 764bc2ab7b51 |
14 | 345a62c48a4b |
15 | 184300d911a3 |
hex | c359e7765eb |
13424431425003 has 64 divisors (see below), whose sum is σ = 20333174400000. Its totient is φ = 8750962344960.
The previous prime is 13424431424977. The next prime is 13424431425017. The reversal of 13424431425003 is 30052413442431.
13424431425003 is a `hidden beast` number, since 1 + 3 + 4 + 2 + 4 + 4 + 3 + 142 + 500 + 3 = 666.
It is a de Polignac number, because none of the positive numbers 2k-13424431425003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13424431425203) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1644945243 + ... + 1644953403.
It is an arithmetic number, because the mean of its divisors is an integer number (317705850000).
Almost surely, 213424431425003 is an apocalyptic number.
13424431425003 is a deficient number, since it is larger than the sum of its proper divisors (6908742974997).
13424431425003 is a wasteful number, since it uses less digits than its factorization.
13424431425003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13617 (or 13611 counting only the distinct ones).
The product of its (nonzero) digits is 138240, while the sum is 36.
Adding to 13424431425003 its reverse (30052413442431), we get a palindrome (43476844867434).
The spelling of 13424431425003 in words is "thirteen trillion, four hundred twenty-four billion, four hundred thirty-one million, four hundred twenty-five thousand, three".
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