Search a number
-
+
13424433457 is a prime number
BaseRepresentation
bin11001000000010100…
…01001100100110001
31021122120102212201011
430200022021210301
5204443123332312
610100032110521
7653445541651
oct144012114461
937576385634
1013424433457
115769819606
122727995441
13135c2b9666
14914c90361
1553883eda7
hex320289931

13424433457 has 2 divisors, whose sum is σ = 13424433458. Its totient is φ = 13424433456.

The previous prime is 13424433431. The next prime is 13424433467. The reversal of 13424433457 is 75433442431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13409871601 + 14561856 = 115801^2 + 3816^2 .

It is an emirp because it is prime and its reverse (75433442431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13424433457 is a prime.

It is not a weakly prime, because it can be changed into another prime (13424433427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712216728 + 6712216729.

It is an arithmetic number, because the mean of its divisors is an integer number (6712216729).

Almost surely, 213424433457 is an apocalyptic number.

It is an amenable number.

13424433457 is a deficient number, since it is larger than the sum of its proper divisors (1).

13424433457 is an equidigital number, since it uses as much as digits as its factorization.

13424433457 is an evil number, because the sum of its binary digits is even.

The product of its digits is 483840, while the sum is 40.

Adding to 13424433457 its reverse (75433442431), we get a palindrome (88857875888).

The spelling of 13424433457 in words is "thirteen billion, four hundred twenty-four million, four hundred thirty-three thousand, four hundred fifty-seven".