13424434025153 has 4 divisors (see below), whose sum is σ = 13424492168580. Its totient is φ = 13424375881728.

The previous prime is 13424434025071. The next prime is 13424434025159. The reversal of 13424434025153 is 35152043442431.

13424434025153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8729619795649 + 4694814229504 = 2954593^2 + 2166752^2 .

It is a cyclic number.

It is not a de Polignac number, because 13424434025153 - 2¹⁸ = 13424433763009 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13424434025153.

It is not an unprimeable number, because it can be changed into a prime (13424434025159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28724000 + ... + 29187617.

It is an arithmetic number, because the mean of its divisors is an integer number (3356123042145).

Almost surely, 2^{13424434025153} is an apocalyptic number.

It is an amenable number.

13424434025153 is a deficient number, since it is larger than the sum of its proper divisors (58143427).

13424434025153 is an equidigital number, since it uses as much as digits as its factorization.

13424434025153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58143426.

The product of its (nonzero) digits is 691200, while the sum is 41.

Adding to 13424434025153 its reverse (35152043442431), we get a palindrome (48576477467584).

The spelling of 13424434025153 in words is "thirteen trillion, four hundred twenty-four billion, four hundred thirty-four million, twenty-five thousand, one hundred fifty-three".