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1342453020134 = 23041757729131
BaseRepresentation
bin10011100010010000011…
…011110111010111100110
311202100002212012022202012
4103202100123313113212
5133443320433121014
62504414151114222
7165663144252362
oct23422033672746
94670085168665
101342453020134
114783708065a6
12198214972972
139979243a5b5
1448d918582a2
1524dc0e57c3e
hex138906f75e6

1342453020134 has 16 divisors (see below), whose sum is σ = 2014676713296. Its totient is φ = 670894195200.

The previous prime is 1342453020091. The next prime is 1342453020143. The reversal of 1342453020134 is 4310203542431.

It is a super-2 number, since 2×13424530201342 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1342453020134.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46068749 + ... + 46097879.

It is an arithmetic number, because the mean of its divisors is an integer number (125917294581).

Almost surely, 21342453020134 is an apocalyptic number.

1342453020134 is a deficient number, since it is larger than the sum of its proper divisors (672223693162).

1342453020134 is a wasteful number, since it uses less digits than its factorization.

1342453020134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39751.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 1342453020134 its reverse (4310203542431), we get a palindrome (5652656562565).

The spelling of 1342453020134 in words is "one trillion, three hundred forty-two billion, four hundred fifty-three million, twenty thousand, one hundred thirty-four".

Divisors: 1 2 3041 6082 7577 15154 29131 58262 23041657 46083314 88587371 177174742 220725587 441451174 671226510067 1342453020134