Base | Representation |
---|---|
bin | 1100001101011010010100… |
… | …0101100111100000111011 |
3 | 1202112101002110010202012002 |
4 | 3003112211011213200323 |
5 | 3224421430340410321 |
6 | 44315052200011215 |
7 | 2553614451413144 |
oct | 303264505474073 |
9 | 52471073122162 |
10 | 13424542513211 |
11 | 43063532a9565 |
12 | 1609924160b0b |
13 | 764c0cb1160b |
14 | 345a738c4acb |
15 | 18430a9d620b |
hex | c35a516783b |
13424542513211 has 4 divisors (see below), whose sum is σ = 13424679030192. Its totient is φ = 13424405996232.
The previous prime is 13424542513157. The next prime is 13424542513237. The reversal of 13424542513211 is 11231524542431.
13424542513211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13424542513211 - 210 = 13424542512187 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13424542513111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68110880 + ... + 68307693.
It is an arithmetic number, because the mean of its divisors is an integer number (3356169757548).
Almost surely, 213424542513211 is an apocalyptic number.
13424542513211 is a deficient number, since it is larger than the sum of its proper divisors (136516981).
13424542513211 is an equidigital number, since it uses as much as digits as its factorization.
13424542513211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 136516980.
The product of its digits is 115200, while the sum is 38.
The spelling of 13424542513211 in words is "thirteen trillion, four hundred twenty-four billion, five hundred forty-two million, five hundred thirteen thousand, two hundred eleven".
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